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3x^2+6x-1080=0
a = 3; b = 6; c = -1080;
Δ = b2-4ac
Δ = 62-4·3·(-1080)
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12996}=114$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-114}{2*3}=\frac{-120}{6} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+114}{2*3}=\frac{108}{6} =18 $
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